darkside 00—Can you please elaborate on T =[1962N]*[0.3m]
There are nuts welded on both 50mm faces.
I am interested in the bearing stress [I presume you mean on the nuts]. You say
Bearing stress=load/bearing area=load/[hole dia*thickness]. Do you mean thickness of the nut or thickness of...
Nvn—Thanks very much for the result. I was apprehensive when designing this frame that the amount of distortion would have been greater than would have been acceptable when the frame was in use, but am relieved with the minimal result
I follow the last part of the calculation of y but I am...
Nvn-Thank you for your explanation and apologies for the delay in replying, but my modem has been down. I have put in another drawing which, I think you will find, is clearer. The total length of the tube is 350mm, so the distance from each stud to the centre of the verticals will be...
A horizontal hollow rectangular mild steel tube 30mm x 50mm with 4mm wall thickness and 350mm long, which is part of a frame has 2 lengths of studding 300mm long , 180mm apart and equidistant from the ends, welded to the 50mm face of the tube.
A total perpendicular load of 400Kgs is...